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Answer: storesDF.coalesce(4)
The question asks for code blocks that return a 4-partition DataFrame from an 8-partition DataFrame without inducing a shuffle. Coalesce (option C) is designed to reduce partitions by merging existing ones without shuffling, making it the correct choice. Repartition (options A, B, D) always triggers a shuffle, even when reducing partitions, which does not meet the requirement of avoiding a shuffle. Option E is invalid because it lacks the necessary partition count argument. Therefore, the only correct option is C.
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Which of the following code blocks will consistently produce a new 4-partition DataFrame from an 8-partition DataFrame named storesDF without causing a shuffle operation?
A
storesDF.repartition(4, "sqft")
B
storesDF.repartition()
C
storesDF.coalesce(4)
D
storesDF.repartition(4)
E
storesDF.coalesce