Answer-first summary for fast verification
Answer: if process_mode == “init“ and not is_table_exist: print(“Start processing ...“)
The correct answer involves using the equality operator `==` instead of the assignment operator `=` in the if-condition. Python's if statement requires conditions to be expressed with logical operators such as `==` for equality, `!=` for inequality, and `not` for negation. The original code mistakenly uses `=` for comparison, which is an assignment operator, leading to the syntax error. The corrected condition checks if `process_mode` is equal to 'init' and `is_table_exist` is not true, using the proper operators. For more information on Python conditions, refer to [Python Conditions](https://www.w3schools.com/python/python_conditions.asp).
Author: LeetQuiz Editorial Team
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A data engineer has developed a Python code block intended to reprocess data under specific conditions. The current if-condition is causing an invalid syntax error. What modification is needed to correct this error?
A
if process_mode = “init“ & not is_table_exist: print(“Start processing ...“)
B
if process_mode = “init“ and not is_table_exist = True: print(“Start processing ...“)
C
if process_mode = “init“ and is_table_exist = False: print(“Start processing ...“)
D
if (process_mode = “init“) and (not is_table_exist): print(“Start processing ...“)
E
if process_mode == “init“ and not is_table_exist: print(“Start processing ...“)
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