Answer-first summary for fast verification
Answer: try:...except:
The correct implementation involves using a `try-except` block to handle potential errors. Here's why: - **`try-except` block**: Encapsulating the division operation (`result = num1 / num2`) within a `try` block allows the program to attempt the operation and catch any exceptions that occur. - **`except ZeroDivisionError`**: By specifying `ZeroDivisionError` in the `except` block, the program specifically catches division by zero errors, making the error handling more precise. - **Error message**: Inside the `except` block, a user-friendly message is printed to inform the user of the error, enhancing the user experience. - **Setting `result` to `None`**: This indicates an error condition, allowing the function to return `None` when a division by zero occurs, thus avoiding program termination. - **Return statement**: The function returns the calculated result if no error occurs, or `None` if a division by zero error is caught, ensuring robust error handling.
Author: LeetQuiz Editorial Team
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To ensure your Python program handles errors gracefully and avoids unexpected termination, how would you implement error handling in the following code snippet?
#program to divide first number by the second number
def division(num1, num2):
________
result = num1 / num2
________
if num2 == 0:
print("Cannot divide by 0. Please try again!")
result = None
return result
output = division(5,0)
#program to divide first number by the second number
def division(num1, num2):
________
result = num1 / num2
________
if num2 == 0:
print("Cannot divide by 0. Please try again!")
result = None
return result
output = division(5,0)
A
try:...catch:
B
try:...error:
C
try:...except:
D
try:...fail:
E
try:...exception:
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