Explanation:
A lambda function in Python is an anonymous function defined with the lambda keyword. It can take any number of arguments but only contains a single expression. The correct syntax for a lambda function that checks if a number is even or odd uses the modulus operator % to determine the remainder of the division by 2. If the remainder is 0, the number is even; otherwise, it's odd. The correct expression places the result before the condition, as in ‘Even‘ if x % 2 == 0 else ‘Odd‘. This makes option B the correct answer.
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Which of the following code blocks correctly demonstrates how to create a lambda function in Python to determine if a number is even or odd?
A
my_func = lambda x: if x % 2 == 0 ‘Even‘ else ‘Odd‘
B
my_func = lambda x: ‘Even‘ if x % 2 == 0 else ‘Odd‘
C
my_func = lambda x: if x / 2 == 0 ‘Even‘ else ‘Odd‘
D
my_func = lambda x: ‘Even‘ if x % 2 = 0 else ‘Odd‘
E
my_func = lambda x: if x % 2 == 0 ‘Even‘ elif x % 2 != 0 ‘Odd‘
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