The correct answer is A because Snowflake documentation explicitly states that the TO_VARIANT function cannot be used directly in an INSERT statement's VALUES clause. Instead, you must use INSERT INTO ... SELECT ... with TO_VARIANT or other conversion functions. Option A correctly describes using a SELECT statement to convert data to VARIANT before inserting. Option B is incorrect as TO_VARIANT cannot be used directly in INSERT. Option C (casting) is also not valid for direct use in INSERT VALUES. Option D (subquery) is essentially the same approach as A but less direct and not the most straightforward method. The community discussion with upvotes supports A, citing official documentation that confirms this limitation.