Answer-first summary for fast verification
Answer: Decrease the value of the epsilon parameter to increase privacy and reduce accuracy
The correct answer is C because in differential privacy, the epsilon (ε) parameter controls the trade-off between privacy and accuracy. A smaller epsilon value adds more noise to the data, which increases privacy by reducing the influence of any individual's data on the aggregated results, but this comes at the cost of reduced accuracy. The community discussion shows a strong consensus (100% of answers and multiple upvoted comments) supporting this understanding, with references to Microsoft documentation confirming that lower epsilon reduces individual data impact and increases privacy. Option A is incorrect because decreasing epsilon increases noise, not decreases it. Option B is wrong because increasing epsilon decreases privacy (opposite of the goal). Option D is incorrect because setting epsilon to 1 doesn't ensure maximum privacy; smaller epsilon values provide stronger privacy protection.
Author: LeetQuiz Editorial Team
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You are training a model on a dataset containing confidential information. To protect individual privacy and minimize the influence of any single user's data on the aggregated results, you must apply a differential privacy parameter. What should you do?
A
Decrease the value of the epsilon parameter to reduce the amount of noise added to the data
B
Increase the value of the epsilon parameter to decrease privacy and increase accuracy
C
Decrease the value of the epsilon parameter to increase privacy and reduce accuracy
D
Set the value of the epsilon parameter to 1 to ensure maximum privacy
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