Financial Risk Manager Part 1

Financial Risk Manager Part 1

Get started today

Ultimate access to all questions.


A life assurance company insures individuals of all ages. A manager compiled the following statistics of the company's insured persons:

Age of insuredMortality (Probability of death) [arbitrary]Portion of company's insured persons
16-200.040.10
21-300.050.29
31-650.100.49
66-990.140.12

Calculate the probability that the dead client was between 66 and 99 years.

TTanishq



Explanation:

To calculate the probability that the dead client was between 66 and 99 years old, we need to use Bayes' theorem:

P(A∣B)=P(B∣A)×P(A)P(B)P(A|B) = \frac{P(B|A) \times P(A)}{P(B)}

Where:

  • Event A: Client was between 66-99 years old
  • Event B: Client died

From the table:

  • P(Dying|66-99) = 0.14
  • P(66-99) = 0.12

First, calculate the marginal probability of dying: P(Dying)=(0.04×0.10)+(0.05×0.29)+(0.10×0.49)+(0.14×0.12)=0.004+0.0145+0.049+0.0168=0.0843P(\text{Dying}) = (0.04 \times 0.10) + (0.05 \times 0.29) + (0.10 \times 0.49) + (0.14 \times 0.12) = 0.004 + 0.0145 + 0.049 + 0.0168 = 0.0843

Now apply Bayes' theorem: P(66-99∣Dying)=P(Dying∣66-99)×P(66-99)P(Dying)=0.14×0.120.0843=0.01680.0843=0.1993P(66\text{-}99|\text{Dying}) = \frac{P(\text{Dying}|66\text{-}99) \times P(66\text{-}99)}{P(\text{Dying})} = \frac{0.14 \times 0.12}{0.0843} = \frac{0.0168}{0.0843} = 0.1993

The probability is approximately 0.199, which corresponds to option B.

Comments

Loading comments...