Financial Risk Manager Part 1

Financial Risk Manager Part 1

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Q.3274 In Toronto, Canada, there is a 90% chance of having a sunny day. What is the probability that there will be exactly 3 sunny days in the next 7 days?

TTanishq



Explanation:

To calculate the probability of having exactly 3 sunny days in the next 7 days, we use the Binomial Distribution formula:

P(X=k)=(nk)pk(1βˆ’p)nβˆ’kP(X = k) = \binom{n}{k} p^k (1-p)^{n-k}

Where:

  • n = 7 (number of days)
  • k = 3 (number of sunny days)
  • p = 0.9 (probability of sunny day)

P(3)=(73)Γ—0.93Γ—(1βˆ’0.9)7βˆ’3P(3) = \binom{7}{3} \times 0.9^3 \times (1 - 0.9)^{7-3}

P(3)=7!3!(7βˆ’3)!Γ—0.93Γ—0.14P(3) = \frac{7!}{3!(7-3)!} \times 0.9^3 \times 0.1^4

P(3)=7Γ—6Γ—53Γ—2Γ—1Γ—0.729Γ—0.0001P(3) = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} \times 0.729 \times 0.0001

P(3)=35Γ—0.729Γ—0.0001=0.00255P(3) = 35 \times 0.729 \times 0.0001 = 0.00255

This is a binomial probability problem where we're looking for exactly 3 successes (sunny days) in 7 independent trials (days), with each trial having a 90% probability of success.

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