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Answer: 3V[Y]
## Explanation To find Cov[E, F], we use the covariance properties: Cov[E, F] = Cov[X + Y, X - Y] Using the bilinearity property of covariance: = Cov[X, X] - Cov[X, Y] + Cov[Y, X] - Cov[Y, Y] Since: - Cov[X, X] = V[X] (variance of X) - Cov[Y, Y] = V[Y] (variance of Y) - Cov[X, Y] = Cov[Y, X] (covariance is symmetric) We get: = V[X] - Cov[X, Y] + Cov[X, Y] - V[Y] = V[X] - V[Y] Given that V[X] = 4V[Y], we substitute: = 4V[Y] - V[Y] = 3V[Y] **Key properties used:** - Cov[X, X] = V[X] - Cov[X, Y] = Cov[Y, X] - Cov[aX + bY, cZ + dW] = acCov[X, Z] + adCov[X, W] + bcCov[Y, Z] + bdCov[Y, W]
Author: Tanishq Prabhu
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Two random variables X and Y are such that V[X] = 4V[Y] and Cov[X,Y] = V[Y]. Let E = X + Y and F = X - Y. Find Cov[E, F].
A
V[Y] - V[X]
B
Cov[X,Y]
C
V[Y]
D
3V[Y]