Financial Risk Manager Part 1

Explanation

To find the expected length of time the contract has been in place (E[Y]), we need to:

1. Find the marginal distribution of Y

   $$f_Y(y) = \int_{-\infty}^{\infty} f_{XY}(x,y)\, dx = \int_2^{10} \frac{1}{64}(10 - xy^2)\, dx$$ $$f_Y(y) = \frac{1}{64} \left[10x - \frac{x^2 y^2}{2}\right]_2^{10} = \frac{1}{64}[80 - 48y^2]$$

   So,

   f_Y(y) = \begin{cases} \frac{1}{64}[80 - 48y^2], & 0 < y < 1 \\ 0, & \text{elsewhere} \end{cases} $`$2`. **Calculate the expectation E[Y]**

   E(Y) = \int_{-\infty}^{\infty} y f_Y(y), dy = \int_0^1 y \cdot \left(\frac{1}{64}[80 - 48y^2]\right) dy

   $$$$

   E(Y) = \frac{1}{64} \int_0^1 (80y - 48y^3) dy = \frac{1}{64} \left[40y^2 - 12y^4\right]_0^1

   $$$$

   E(Y) = \frac{1}{64}[40 - 12] = \frac{28}{64} = \frac{7}{16} = 0.4375

   $$$$

Therefore, the expected length of time the contract has been in place is 0.4375.