Financial Risk Manager Part 1

Financial Risk Manager Part 1

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Construct a 95% confidence interval for the future value of a pension fund where the number of simulations is 100, the mean ending value is 400,000,andthestandarddeviationis400,000, and the standard deviation is 23,300.

TTanishq



Explanation:

Explanation

The confidence interval is constructed using the normal distribution, not the student's t-distribution because n is large (in line with the central limit theorem).

The interval is given by:

XΛ‰βˆ’1.96βˆ—(sN),XΛ‰+1.96βˆ—(sN)\bar{X} - 1.96 * \left(\frac{s}{\sqrt{N}}\right), \bar{X} + 1.96 * \left(\frac{s}{\sqrt{N}}\right)

Thus,

CI=$400,000βˆ’1.96($23,300100),$400,000+1.96($23,300100)CI = \$400,000 - 1.96\left(\frac{\$23,300}{\sqrt{100}}\right), \$400,000 + 1.96\left(\frac{\$23,300}{\sqrt{100}}\right)

=$400,000βˆ’1.96($2,330),$400,000+1.96($2,330)= \$400,000 - 1.96(\$2,330), \$400,000 + 1.96(\$2,330)

=$400,000βˆ’$4,566.8,$400,000+$4,566.8= \$400,000 - \$4,566.8, \$400,000 + \$4,566.8

=($395,433.2,$404,566.8)= (\$395,433.2, \$404,566.8)

Key points:

  • For large sample sizes (n β‰₯ 30), we use the normal distribution (z-distribution)
  • The 95% confidence level corresponds to z = 1.96
  • The standard error is calculated as s/√n = 23,300/√100=23,300/√100 = 2,330
  • The margin of error is 1.96 Γ— 2,330=2,330 = 4,566.8

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