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Answer: [41.6 days; 48.4 days]
## Explanation To calculate the 95% confidence interval for the population mean, we use the formula: **Confidence Interval = Sample Mean ± (Z-value × Standard Error)** ### Step 1: Calculate Standard Error Standard Error = σ / √n = 19 / √121 = 19 / 11 = 1.7273 ≈ 1.73 ### Step 2: Identify Z-value For a 95% confidence interval, the Z-value is 1.96 ### Step 3: Calculate Margin of Error Margin of Error = Z-value × Standard Error = 1.96 × 1.73 = 3.3908 ≈ 3.4 ### Step 4: Calculate Confidence Interval Lower Limit = 45 - 3.4 = 41.6 days Upper Limit = 45 + 3.4 = 48.4 days Therefore, the 95% confidence interval is **[41.6 days; 48.4 days]** **Key Points:** - We use Z-distribution because the population is normally distributed - Sample size (n=121) is sufficiently large - Standard error decreases with larger sample sizes - The confidence interval represents the range where we're 95% confident the true population mean lies
Author: Tanishq Prabhu
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A sample of 121 applicants received the Canadian travel visa in 45 days on average. Suppose the population is normally distributed, and the standard deviation of the sample is 19, then what is the 95% confidence interval for the population mean?
A
[44.7 days; 45.3 days]
B
[41.6 days; 48.4 days]
C
[42.2 days; 47.8 days]
D
[40.1 days; 49.8 days]
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