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A sample of 121 applicants received the Canadian travel visa in 45 days on average. Suppose the population is normally distributed, and the standard deviation of the sample is 19, then what is the 95% confidence interval for the population mean?
A
[44.7 days; 45.3 days]
B
[41.6 days; 48.4 days]
C
[42.2 days; 47.8 days]
D
[40.1 days; 49.8 days]
Explanation:
To calculate the 95% confidence interval for the population mean, we use the formula:
Confidence Interval = Sample Mean ± (Z-value × Standard Error)
Standard Error = σ / √n = 19 / √121 = 19 / 11 = 1.7273 ≈ 1.73
For a 95% confidence interval, the Z-value is 1.96
Margin of Error = Z-value × Standard Error = 1.96 × 1.73 = 3.3908 ≈ 3.4
Lower Limit = 45 - 3.4 = 41.6 days Upper Limit = 45 + 3.4 = 48.4 days
Therefore, the 95% confidence interval is [41.6 days; 48.4 days]
Key Points: