Financial Risk Manager Part 1

Financial Risk Manager Part 1

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A sample of 100 students is currently renting rooms in the mean distance of 18 miles from a small U.S. College. Assuming that the population is normally distributed and the standard deviation of the sample is 14 miles, what is the 99% confidence interval for the population mean?

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Explanation:

Explanation

To calculate the 99% confidence interval for the population mean, we use the formula:

Confidence Interval = Sample Mean ± (Z-score × Standard Error)

Step 1: Calculate Standard Error

Standard Error = Standard DeviationSample Size=14100=1410=1.4\frac{\text{Standard Deviation}}{\sqrt{\text{Sample Size}}} = \frac{14}{\sqrt{100}} = \frac{14}{10} = 1.4

Step 2: Find Z-score for 99% Confidence Level

For a 99% confidence interval, the Z-score (reliability factor) is 2.58

Step 3: Calculate Margin of Error

Margin of Error = Z-score × Standard Error = 2.58 × 1.4 = 3.612

Step 4: Calculate Confidence Interval

  • Lower Limit = Sample Mean - Margin of Error = 18 - 3.612 = 14.388 ≈ 14.4 miles
  • Upper Limit = Sample Mean + Margin of Error = 18 + 3.612 = 21.612 ≈ 21.6 miles

Therefore, the 99% confidence interval is [14.4 miles; 21.6 miles]

Key Points:

  • We use Z-distribution because the population standard deviation is known
  • The sample size (n=100) is sufficiently large
  • The confidence interval represents the range where we are 99% confident the true population mean lies

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