
Answer-first summary for fast verification
Answer: [14.4 miles; 21.6 miles]
## Explanation To calculate the 99% confidence interval for the population mean, we use the formula: **Confidence Interval = Sample Mean ± (Z-score × Standard Error)** ### Step 1: Calculate Standard Error Standard Error = $\frac{\text{Standard Deviation}}{\sqrt{\text{Sample Size}}} = \frac{14}{\sqrt{100}} = \frac{14}{10} = 1.4$ ### Step 2: Find Z-score for 99% Confidence Level For a 99% confidence interval, the Z-score (reliability factor) is 2.58 ### Step 3: Calculate Margin of Error Margin of Error = Z-score × Standard Error = 2.58 × 1.4 = 3.612 ### Step 4: Calculate Confidence Interval - Lower Limit = Sample Mean - Margin of Error = 18 - 3.612 = 14.388 ≈ 14.4 miles - Upper Limit = Sample Mean + Margin of Error = 18 + 3.612 = 21.612 ≈ 21.6 miles Therefore, the 99% confidence interval is **[14.4 miles; 21.6 miles]** **Key Points:** - We use Z-distribution because the population standard deviation is known - The sample size (n=100) is sufficiently large - The confidence interval represents the range where we are 99% confident the true population mean lies
Author: Tanishq Prabhu
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A sample of 100 students is currently renting rooms in the mean distance of 18 miles from a small U.S. College. Assuming that the population is normally distributed and the standard deviation of the sample is 14 miles, what is the 99% confidence interval for the population mean?
A
[15.26 miles; 20.74 miles]
B
[16.6 miles; 19.4 miles]
C
[14.4 miles; 21.6 miles]
D
[12.8 miles; 23.6 miles]
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