
Financial Risk Manager Part 1
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Assuming that mutual fund returns are normally distributed and using a z-table, what is the correct probability of earning a return in excess of 20%?
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TTanishq
Explanation:
Explanation
To find the probability of earning a return in excess of 20% for each mutual fund, we need to calculate the z-score for each fund and use the z-table to find the corresponding probability.
Z-Score Formula:
[ Z = \frac{\text{Desired Return} - \text{Mean Return}}{\text{Standard Deviation}} ]
Calculations:
Fund X:
- Mean = 25%, Std. Dev. = 2%
- [ Z = \frac{20% - 25%}{2%} = \frac{-5%}{2%} = -2.5 ]
- P(Z < -2.5) β 0.0062 (from z-table)
- P(X > 20%) = 1 - P(Z < -2.5) = 1 - 0.0062 = 0.9938 = 99.38%
Fund Y:
- Mean = 24.8%, Std. Dev. = 3%
- [ Z = \frac{20% - 24.8%}{3%} = \frac{-4.8%}{3%} = -1.6 ]
- P(Z < -1.6) β 0.0548 (from z-table)
- P(Y > 20%) = 1 - P(Z < -1.6) = 1 - 0.0548 = 0.9452 = 94.52%
Fund Z:
- Mean = 26%, Std. Dev. = 4%
- [ Z = \frac{20% - 26%}{4%} = \frac{-6%}{4%} = -1.5 ]
- P(Z < -1.5) β 0.0668 (from z-table)
- P(Z > 20%) = 1 - P(Z < -1.5) = 1 - 0.0668 = 0.9332 = 93.32%
Analysis of Options:
- Option A (1.60% for Fund Y) - Incorrect, this is approximately P(Z < -1.6) not P(Y > 20%)
- Option B (94.52% for Fund Z) - Incorrect, this is actually the probability for Fund Y
- Option C (99.38% for Fund X) - CORRECT - Matches our calculation for Fund X
- Option D (11.6% for Fund Y) - Incorrect, this doesn't match any of our calculated probabilities
Therefore, the correct answer is C - 99.38% for Fund X.
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