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Financial Risk Manager Part 1

Financial Risk Manager Part 1

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Given a model with two independent variables: Yi=α+β1X1i+β2X2i+eiY_i = \alpha + \beta_1 X_{1i} + \beta_2 X_{2i} + e_iYi​=α+β1​X1i​+β2​X2i​+ei​, what is the value of the correlation coefficient between X1X_1X1​ and X2X_2X2​ so that the value of the variance inflation factor is 15?

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Explanation:

The variance inflation factor (VIF) for a variable in a regression model is given by:

VIF=11−Rj2\text{VIF} = \frac{1}{1 - R_j^2}VIF=1−Rj2​1​

Where Rj2R_j^2Rj2​ is the coefficient of determination from regressing variable jjj on the other independent variables. In this case with two independent variables, Rj2R_j^2Rj2​ equals the squared correlation coefficient between X1X_1X1​ and X2X_2X2​:

Rj2=ρX1X22R_j^2 = \rho_{X_1 X_2}^2Rj2​=ρX1​X2​2​

Given that VIF = 15:

11−ρX1X22=15\frac{1}{1 - \rho_{X_1 X_2}^2} = 151−ρX1​X2​2​1​=15

Solving for ρX1X2\rho_{X_1 X_2}ρX1​X2​​:

1−ρX1X22=1151 - \rho_{X_1 X_2}^2 = \frac{1}{15}1−ρX1​X2​2​=151​

ρX1X22=1−115=1415\rho_{X_1 X_2}^2 = 1 - \frac{1}{15} = \frac{14}{15}ρX1​X2​2​=1−151​=1514​

ρX1X2=1415=0.9333=0.9661\rho_{X_1 X_2} = \sqrt{\frac{14}{15}} = \sqrt{0.9333} = 0.9661ρX1​X2​​=1514​​=0.9333​=0.9661

Therefore, the correlation coefficient between X1X_1X1​ and X2X_2X2​ that gives a VIF of 15 is 0.9661.

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