According to the Jarque-Bera (JB) test, the test statistic is given by: $ \text{JB} = (T - 1) \left( \frac{\hat{S}^2}{6} + \frac{(\hat{k} - 3)^2}{24} \right) $ So, $ \text{JB} = (100 - 1) \left( \frac{0.35^2}{6} + \frac{(3.04 - 3)^2}{24} \right) = 2.028 $ Recall that JB ~ $\chi^2_2$ so that critical value at 5% with 2 degrees of freedom (df) is 5.991 (which can be seen from a chi-square table). Since the test statistic is less than the critical value, we fail to reject the null hypothesis that the returns are normal, and hence the analyst can use the normal distributions in analyzing the returns. What is the calculated Jarque-Bera test statistic value? | Financial Risk Manager Part 1 Quiz - LeetQuiz