Financial Risk Manager Part 1

Financial Risk Manager Part 1

Get started today

Ultimate access to all questions.


Assume that you want to generate random variables from U(-1,5) using random variables from U(0,1). What is the corresponding random variable of 0.10 ~ U(0,1)?

TTanishq



Explanation:

Explanation

To generate random variables from U(-1,5) using random variables from U(0,1), we use the inverse transform method.

Step 1: Find the CDF of X ~ U(-1,5)

For a uniform distribution U(a,b), the CDF is: F(x)=xβˆ’abβˆ’a,fora≀x≀bF(x) = \frac{x - a}{b - a}, \quad \text{for} \quad a \leq x \leq b

Given X ~ U(-1,5), where a = -1 and b = 5: F(x)=xβˆ’(βˆ’1)5βˆ’(βˆ’1)=x+16F(x) = \frac{x - (-1)}{5 - (-1)} = \frac{x + 1}{6}

Step 2: Apply the inverse transform method

Let U ~ U(0,1), then we solve for X: U=F(X)=X+16U = F(X) = \frac{X + 1}{6} X=6Uβˆ’1X = 6U - 1

Step 3: Calculate for U = 0.10

X=6Γ—0.10βˆ’1=0.60βˆ’1=βˆ’0.40X = 6 \times 0.10 - 1 = 0.60 - 1 = -0.40

Therefore, the corresponding random variable for U = 0.10 is -0.40, which corresponds to option C.

Verification

The transformation X = 6U - 1 maps:

  • When U = 0 β†’ X = -1 (lower bound)
  • When U = 1 β†’ X = 5 (upper bound)
  • When U = 0.10 β†’ X = -0.40 (as calculated)

Comments

Loading comments...