
Answer-first summary for fast verification
Answer: The GARCH (1, 1) model.
## Explanation ### Model Formulas: - **EWMA**: $\sigma_n^2 = \lambda \sigma_{n-1}^2 + (1-\lambda)r_{n-1}^2$ - **GARCH(1,1)**: $\sigma_n^2 = \omega + \alpha r_{n-1}^2 + \beta \sigma_{n-1}^2$ ### Given Conditions: - Both models have the same parameter on $\sigma_{n-1}^2$ (same $\beta$) - $\sigma_{n-1}^2 = r_{n-1}^2$ - Current variance is above long-run variance ### Analysis: In GARCH(1,1), the long-run variance is $\frac{\omega}{1-\alpha-\beta}$. When current variance is above long-run variance, the GARCH model will forecast a lower variance than EWMA because: 1. GARCH has a **mean-reversion** component ($\omega$) that pulls the forecast back toward the long-run average 2. EWMA has **no mean-reversion** - it's a weighted average that doesn't revert to any long-term level 3. With current variance above long-run level, GARCH's mean-reversion effect will reduce the forecast compared to EWMA Therefore, **GARCH(1,1) will forecast lower volatility** than EWMA under these conditions.
Author: LeetQuiz Editorial Team
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The exponentially weighted moving average (EWMA) and the generalized autoregressive conditional heteroscedasticity (GARCH) are two well-recognized volatility models. Suppose we have a EWMA and a GARCH (1, 1). Both have the same parameter attached on the , and . Further assume that is currently above the long-run variance, which model will forecast a lower day volatility?
A
The EWMA model.
B
The GARCH (1, 1) model.
C
The forecast is the same for both models.
D
Further information is required in order to make the comparison.
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