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Financial Risk Manager Part 1

Financial Risk Manager Part 1

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Q-42. Solution: A

In this case S0=50S_0 = 50S0​=50, K=50K = 50K=50, r=0.1r = 0.1r=0.1, σ=0.3\sigma = 0.3σ=0.3, T=0.25T = 0.25T=0.25, and

d1=ln⁡(50/50)+(0.1+0.09/2)⋅0.250.30.25=0.2417d_1 = \frac{\ln(50/50) + (0.1 + 0.09/2) \cdot 0.25}{0.3\sqrt{0.25}} = 0.2417d1​=0.30.25​ln(50/50)+(0.1+0.09/2)⋅0.25​=0.2417 d2=d1−0.30.25=0.0917d_2 = d_1 - 0.3\sqrt{0.25} = 0.0917d2​=d1​−0.30.25​=0.0917

The European put price is:

50N(−0.0917)e−0.1×0.25−50N(−0.2417)50N(-0.0917)e^{-0.1 \times 0.25} - 50N(-0.2417)50N(−0.0917)e−0.1×0.25−50N(−0.2417) =50×0.4634e−0.1×0.25−50×0.4045=2.37= 50 \times 0.4634e^{-0.1 \times 0.25} - 50 \times 0.4045 = 2.37=50×0.4634e−0.1×0.25−50×0.4045=2.37

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