
Explanation:
Given:
Step 1: Find P(A) and P(B) Using the conditional probability formula: P(B|A) = P(A∩B) / P(A) 80% = 4% / P(A) P(A) = 4% / 80% = 5%
Since P(A) = P(B), then P(B) = 5%
Step 2: Find P(A∪B) Using the addition rule: P(A∪B) = P(A) + P(B) - P(A∩B) P(A∪B) = 5% + 5% - 4% = 6%
Step 3: Find P(neither occurs) P(neither) = 1 - P(A∪B) = 1 - 6% = 94%
Therefore, the probability that neither event occurs is 94%.
Suppose there are two events A and B. The probability of A occurrence equals that of B. P(AB) = 4%, if event A occurred, the probability of B occurs is 80%. What is the probability of neither occurs?
A
86%
B
90%
C
94%
D
96%
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