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Answer: The risk neutral probability of an upward movement is not affected by reducing the length of time step.
## Explanation In the binomial option pricing model: - **u (up factor)** and **d (down factor)** are calculated as: - u = e^(σ√Δt) - d = e^(-σ√Δt) = 1/u - **Risk-neutral probability (p)** is calculated as: - p = (e^(rΔt) - d) / (u - d) When we reduce Δt from 1/2 to 1/12: 1. **u decreases** (not increases) because u = e^(σ√Δt) and √Δt decreases 2. **d increases** (not decreases) because d = e^(-σ√Δt) and √Δt decreases 3. **Option value changes** - with smaller time steps, the binomial tree becomes more granular and the option price converges to the Black-Scholes value 4. **Risk-neutral probability (p) remains approximately the same** - this is the correct answer because: - p = (e^(rΔt) - d) / (u - d) - As Δt becomes smaller, both numerator and denominator change proportionally - For small Δt, p ≈ (1 + rΔt - (1 - σ√Δt + σ²Δt/2)) / ((1 + σ√Δt + σ²Δt/2) - (1 - σ√Δt + σ²Δt/2)) - This simplifies to p ≈ (rΔt + σ√Δt) / (2σ√Δt) = 1/2 + (r - σ²/2)√Δt/(2σ) - The change in p is very small and often negligible for practical purposes The key insight is that while u and d change significantly with Δt, the risk-neutral probability p is relatively stable and not meaningfully affected by changes in time step size.
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Brandon, FRM, is tuning the binomial tree option pricing model used for pricing a European call option. After changing the length of time step, Δt, from 1/2 to 1/12, what will be the impact on the model?
A
The option value as a model output will remain the same after reducing the length of time step.
B
The u used for constructing the binomial tree will increase after reducing the length of time step.
C
The d used for constructing the binomial tree will increase after reducing the length of time step.
D
The risk neutral probability of an upward movement is not affected by reducing the length of time step.
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