Explanation

Given:

• P(A) = P(B) (equal probabilities)
• P(A∩B) = 4% = 0.04
• P(B|A) = 80% = 0.8

From conditional probability: P(B|A) = P(A∩B)/P(A) So: 0.8 = 0.04/P(A) Therefore: P(A) = 0.04/0.8 = 0.05

Since P(A) = P(B), we have P(B) = 0.05

Now, using the addition rule: P(A∪B) = P(A) + P(B) - P(A∩B) = 0.05 + 0.05 - 0.04 = 0.06

Probability that neither occurs = 1 - P(A∪B) = 1 - 0.06 = 0.94 = 94%

Answer: C (94%)