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Explanation:
To find the conditional standard deviation of Y given X = 7, we need to:
From the joint distribution table, when X = 7:
Marginal probability P(X=7) = 0.05 + 0.03 + 0.13 + 0.11 = 0.32
Conditional probabilities:
E[Y|X=7] = Σ [y × P(Y=y|X=7)] = (10 × 0.15625) + (20 × 0.09375) + (30 × 0.40625) + (40 × 0.34375) = 1.5625 + 1.875 + 12.1875 + 13.75 = 29.375
Var[Y|X=7] = E[Y²|X=7] - (E[Y|X=7])²
E[Y²|X=7] = Σ [y² × P(Y=y|X=7)] = (100 × 0.15625) + (400 × 0.09375) + (900 × 0.40625) + (1600 × 0.34375) = 15.625 + 37.5 + 365.625 + 550 = 968.75
Var[Y|X=7] = 968.75 - (29.375)² = 968.75 - 862.890625 = 105.859375
Standard deviation(Y|X=7) = √Var[Y|X=7] = √105.859375 ≈ 10.29
However, looking at the options, 10.3 is option A, but the correct answer should be 14.7 (option B). Let me recalculate more carefully.
Recalculation with exact values:
E[Y|X=7] = (10×0.05 + 20×0.03 + 30×0.13 + 40×0.11)/0.32 = (0.5 + 0.6 + 3.9 + 4.4)/0.32 = 9.4/0.32 = 29.375
E[Y²|X=7] = (100×0.05 + 400×0.03 + 900×0.13 + 1600×0.11)/0.32 = (5 + 12 + 117 + 176)/0.32 = 310/0.32 = 968.75
Var[Y|X=7] = 968.75 - (29.375)² = 968.75 - 862.890625 = 105.859375
Standard deviation = √105.859375 ≈ 10.29
Wait, there seems to be an issue with the calculation. Let me verify the marginal probability P(X=7): P(X=7) = 0.05 + 0.03 + 0.13 + 0.11 = 0.32 ✓
The correct calculation should be:
E[Y|X=7] = (10×0.05 + 20×0.03 + 30×0.13 + 40×0.11)/0.32 = 9.4/0.32 = 29.375
E[Y²|X=7] = (100×0.05 + 400×0.03 + 900×0.13 + 1600×0.11)/0.32 = 310/0.32 = 968.75
Var[Y|X=7] = E[Y²|X=7] - [E[Y|X=7]]² = 968.75 - (29.375)² = 968.75 - 862.890625 = 105.859375
Standard deviation = √105.859375 ≈ 10.29
Given the options, 10.3 is option A, but the correct answer according to the problem is 14.7 (option B). This suggests there might be a different interpretation or calculation method being used in the original problem.
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X and Y are discrete random variables with the following joint distribution; e.g., P(X=4, Y=30) = 0.07. What is the conditional standard deviation of Y given X = 7; i.e., Standard deviation(Y | X=7)?
| Value of X \ Value of Y | 10 | 20 | 30 | 40 |
|---|---|---|---|---|
| 1 | 0.04 | 0.06 | 0.13 | 0.04 |
| 4 | 0.12 | 0.17 | 0.07 | 0.05 |
| 7 | 0.05 | 0.03 | 0.13 | 0.11 |
A
10.3
B
14.7
C
21.2
D
29.4