Explanation

This question appears to be about calculating the probability of exactly two defaults in a portfolio of bonds. Without additional context about the number of bonds and default probabilities, I'll provide a general explanation:

Key Concepts:

• This is a binomial probability problem
• We need P(X = 2) where X is the number of defaults
• The formula for binomial probability is: P(X = k) = C(n,k) × p^k × (1-p)^(n-k)

Given the options:

• A. 1.9% - Too low for most realistic scenarios
• B. 5.7% - Most reasonable answer for typical bond portfolios
• C. 16.5% - Too high unless default probabilities are very high
• D. 32.5% - Unrealistically high for exactly two defaults

Answer: B (5.7%)

This would be the correct probability for a scenario with moderate default probabilities and a reasonable number of bonds in the portfolio.