Financial Risk Manager Part 1

Get started today

Ultimate access to all questions.

Quick Answer

Answer-first summary for fast verification

Answer: 0.80

Since the events are mutually exclusive: $$P(A \cup B) = P(A) + P(B)$$ $$= 0.3 + 0.5 = 0.80$$ Note: If the two events were not mutually exclusive, we would use the formula: $$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$

Author: Nikitesh Somanthe

Quick Answer

Answer-first summary for fast verification

Answer: 0.80

Since the events are mutually exclusive: $$P(A \cup B) = P(A) + P(B)$$ $$= 0.3 + 0.5 = 0.80$$ Note: If the two events were not mutually exclusive, we would use the formula: $$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$

Author: Nikitesh Somanthe

Comments (0)

No comments yet.

Get started today

Ultimate access to all questions.

Comments (0)

No comments yet.

Events $A$ and $B$ are mutually exclusive events and $P(A) = 0.3$ while $P(B) = 0.5$ .
Calculate $P(A \cup B)$ .

Other

Community

NNikitesh

Last updated: February 8, 2026 at 16:56

0

A

0.2

11.8%

B

0.35

17.6%

C

0.5

11.8%

D

0.80

58.8%

Powered ByGPT 5.4

Financial Risk Manager Part 1

Get started today

Quick Answer

Quick Answer

Comments (0)

Get started today

Comments (0)

Events AAA and BBB are mutually exclusive events and P(A)=0.3P(A) = 0.3P(A)=0.3 while P(B)=0.5P(B) = 0.5P(B)=0.5. Calculate P(A∪B)P(A \cup B)P(A∪B).

Events $A$ and $B$ are mutually exclusive events and $P(A) = 0.3$ while $P(B) = 0.5$ .
Calculate $P(A \cup B)$ .