Explanation:
Since the events are mutually exclusive:
P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B)P(A∪B)=P(A)+P(B)
=0.3+0.5=0.80= 0.3 + 0.5 = 0.80=0.3+0.5=0.80
Note: If the two events were not mutually exclusive, we would use the formula:
P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B)P(A∪B)=P(A)+P(B)−P(A∩B)
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Events AAA and BBB are mutually exclusive events and P(A)=0.3P(A) = 0.3P(A)=0.3 while P(B)=0.5P(B) = 0.5P(B)=0.5. Calculate P(A∪B)P(A \cup B)P(A∪B).
A
0.2
B
0.35
C
0.5
D
0.80
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