Answer: 25/36

The probability that it takes at least 3 rolls to get a 6 is calculated as: P(at least 3 rolls) = 1 - P(less than 3 rolls) P(less than 3 rolls) = P(getting 6 in 1st roll) + P(getting 6 in 2nd roll) P(getting 6 in 1st roll) = 1/6 P(getting 6 in 2nd roll) = (5/6) × (1/6) = 5/36 So P(less than 3 rolls) = 1/6 + 5/36 = 6/36 + 5/36 = 11/36 Therefore, P(at least 3 rolls) = 1 - 11/36 = 25/36

Author: Nikitesh Somanthe