Answer: 200

## Explanation For a uniform distribution on the interval [0,500]: 1. **Median calculation**: The median is the 50th percentile. For a uniform distribution on [a,b], the p-th percentile is given by: $$\text{Percentile}_p = a + p \times (b-a)$$ For p = 0.5 (50th percentile): $$\text{Median} = 0 + 0.5 \times (500-0) = 0.5 \times 500 = 250$$ 2. **10th percentile calculation**: $$\text{10th percentile} = 0 + 0.1 \times (500-0) = 0.1 \times 500 = 50$$ 3. **Difference calculation**: $$\text{Difference} = \text{Median} - \text{10th percentile} = 250 - 50 = 200$$ Therefore, the correct answer is **B (200)**. **Key points**: - Uniform distribution percentiles are linear interpolations between the minimum and maximum values - The median (50th percentile) is exactly halfway between the minimum and maximum - The 10th percentile is 10% of the way from the minimum to the maximum

Author: Nikitesh Somanthe