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Insurance claims in a certain class of business are modeled using a normal distribution with mean $3,000 and a standard deviation of $400. Calculate the probability that the next claim received will exceed $3,500.
A
0.8944
B
0.25
C
0.75
D
0.1056
Explanation:
Step-by-step solution:
Given: X ~ N(3000, 400²) where μ = 3000 and σ = 400
Standardize the value: We need P(X > 3500)
Z = (X - μ)/σ = (3500 - 3000)/400 = 500/400 = 1.25
Find the probability: P(X > 3500) = P(Z > 1.25)
Using the standard normal distribution table: P(Z < 1.25) = 0.8944
Therefore: P(Z > 1.25) = 1 - P(Z < 1.25) = 1 - 0.8944 = 0.1056
Interpretation: There's approximately a 10.56% probability that the next claim will exceed $3,500.
Key concept: This is a standard normal distribution problem where we convert the raw score to a z-score and use the standard normal distribution table to find probabilities.