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Given a binomial random variable with (E(X) = 2) and (Var(X) = 1.5), calculate (P(X=5)).
A
0.015
B
0.023
C
0.039
D
0.047
Explanation:
For a binomial random variable X with parameters n (number of trials) and p (probability of success):
From the variance formula: Var(X) = np(1-p) = 2(1-p) = 1.5
Solving for p: 2(1-p) = 1.5 1-p = 0.75 p = 0.25
Now, using E(X) = np = 2: n × 0.25 = 2 n = 8
So we have n = 8, p = 0.25
Calculating P(X = 5):
P(X = 5) = C(8,5) × (0.25)^5 × (0.75)^3
Where C(8,5) = 8!/(5!×3!) = 56
P(X = 5) = 56 × (0.25)^5 × (0.75)^3 = 56 × 0.0009765625 × 0.421875 = 56 × 0.0004119873046875 = 0.0230712890625 ≈ 0.023
Therefore, the correct answer is B. 0.023.