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The yearly profits of the two firms A and B can be summarized in the following probability matrix.
| Company A (X₁) Profits | ||||
|---|---|---|---|---|
| -1 Million | 0 Million | 2 Million | 4 Million | |
| Company B (X₂) Profits | ||||
| -50 Million | 0.0197 | 0.0395 | 0.010 | 0.002 |
| 0 Million | 0.0390 | 0.230 | 0.124 | 0.0298 |
| 10 Million | 0.011 | 0.127 | 0.144 | 0.0662 |
| 100 Million | 0 | 0.0309 | 0.0656 | 0.0618 |
What is the covariance of company A and B given that ?
A
24.56
B
23.43
Explanation:
To calculate the covariance between company A and B, we need to use the formula:
Cov(X₁, X₂) = E(X₁X₂) - E(X₁)E(X₂)
We are given that E(X₁X₂) = 43.23, so we need to calculate E(X₁) and E(X₂) from the joint probability distribution table.
First, we need to find the marginal distribution of X₁ by summing probabilities across each column (for each value of X₁).
Values of X₁: -1, 0, 2, 4 (in millions)
Marginal probabilities for X₁:
Check sum: 0.0697 + 0.4274 + 0.3436 + 0.1598 = 1.0005 (≈ 1, minor rounding differences)
E(X₁) = Σ [x₁ × P(X₁ = x₁)] = (-1 × 0.0697) + (0 × 0.4274) + (2 × 0.3436) + (4 × 0.1598) = -0.0697 + 0 + 0.6872 + 0.6392 = 1.2567
Now find the marginal distribution of X₂ by summing probabilities across each row (for each value of X₂).
Values of X₂: -50, 0, 10, 100 (in millions)
Marginal probabilities for X₂:
Check sum: 0.0712 + 0.4228 + 0.3482 + 0.1583 = 1.0005 (≈ 1)
E(X₂) = Σ [x₂ × P(X₂ = x₂)] = (-50 × 0.0712) + (0 × 0.4228) + (10 × 0.3482) + (100 × 0.1583) = -3.56 + 0 + 3.482 + 15.83 = 15.752
Cov(X₁, X₂) = E(X₁X₂) - E(X₁)E(X₂) = 43.23 - (1.2567 × 15.752) = 43.23 - 19.796 = 23.434
Rounding to two decimal places: 23.43
Therefore, the correct answer is B. 23.43.
Note: The question states that E(X₁X₂) = 43.23 is given, which saves us from having to calculate it directly from the joint distribution table. This value would be computed as ΣΣ x₁x₂ × P(X₁=x₁, X₂=x₂) across all combinations in the table.