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Three random variables X, Y, and Z have equal variance of σ² = 2. X is independent of both Y and Z, and that Y and Z are correlated with a correlation coefficient of 0.8. What is the covariance between Z and V given that V=3X-2Y.
A
4.1
B
-4.3
C
3.2
D
-3.2
Explanation:
We need to find Cov(Z, V) where V = 3X - 2Y.
Using the linearity property of covariance:
Cov(Z, V) = Cov(Z, 3X - 2Y) = 3Cov(Z, X) - 2Cov(Z, Y)
We are told that X is independent of both Y and Z, so:
Cov(Z, X) = 0 (since independence implies zero covariance)
Thus:
Cov(Z, V) = 3 × 0 - 2Cov(Z, Y) = -2Cov(Z, Y)
We know the correlation coefficient between Y and Z is ρ(Y,Z) = 0.8, and both have variance σ² = 2.
Recall the relationship between covariance and correlation:
ρ(Y,Z) = Cov(Y,Z) / (σ_Y × σ_Z)
Since both have equal variance σ² = 2, their standard deviations are: σ_Y = σ_Z = √2
Therefore: Cov(Y,Z) = ρ(Y,Z) × σ_Y × σ_Z = 0.8 × √2 × √2 = 0.8 × 2 = 1.6
Note: Cov(Z,Y) = Cov(Y,Z) = 1.6
Cov(Z, V) = -2 × Cov(Z, Y) = -2 × 1.6 = -3.2
Therefore, the correct answer is -3.2 (Option D).