The Ljung-Box Q-statistic is calculated using the formula: $Q = n(n+2) \sum_{k=1}^{h} \frac{\rho_k^2}{n-k}$

Given: $n = 333$ $k=1: \frac{0.12^2}{333-1} = \frac{0.0144}{332} \approx 0.00004337$ $k=2: \frac{(-0.17)^2}{333-2} = \frac{0.0289}{331} \approx 0.00008731$ $k=3: \frac{(-0.09)^2}{333-3} = \frac{0.0081}{330} \approx 0.00002455$

Sum of the terms: $0.00004337 + 0.00008731 + 0.00002455 = 0.00015523$

Now, multiply by $n(n+2)$: $n(n+2) = 333 \times 335 = 111,555$ $Q = 111,555 \times 0.00015523 \approx 17.316 \approx 17.32$

The closest value is 17.32.