Financial Risk Manager Part 1

Get started today

Ultimate access to all questions.

Explanation:

To find the probability of a woman currently aged 30 dying between the ages of 31 and 32, we calculate the joint probability that she survives the year from age 30 to 31 and then dies in the year from age 31 to 32.

Given:

Probability of dying at age 30 ( $q_{30}$ ) = 0.001312
Probability of surviving age 30 ( $p_{30}$ ) = $1 - 0.001312 = 0.998688$
Probability of dying at age 31 ( $q_{31}$ ) = 0.001345

Probability of dying between ages 31 and 32 for a person aged 30: $P = p_{30} \times q_{31}$ $P = 0.998688 \times 0.001345 \approx 0.0013432$

The closest option is 0.001343.

Explanation:

Given:

Probability of dying at age 30 ( $q_{30}$ ) = 0.001312
Probability of surviving age 30 ( $p_{30}$ ) = $1 - 0.001312 = 0.998688$
Probability of dying at age 31 ( $q_{31}$ ) = 0.001345

Probability of dying between ages 31 and 32 for a person aged 30: $P = p_{30} \times q_{31}$ $P = 0.998688 \times 0.001345 \approx 0.0013432$

The closest option is 0.001343.

Comments (0)

No comments yet.

Q.31 The following data gives the mortality expectancy among women in India in 1954.

Age in years Probability of death within one year Life expectancy
30 0.001312 47.52
31 0.001345 46.59
32 0.001383 45.65
33 0.001415 44.73

Which of the following is the probability of a woman who is aged 30 dying between ages 31 and 32?

Age in years	Probability of death within one year	Life expectancy
30	0.001312	47.52
31	0.001345	46.59
32	0.001383	45.65
33	0.001415	44.73

Exam-Like

Community

TTitan

Last updated: May 18, 2026 at 04:39

0.001312

0.001345

0.001343

0.001348