We use Bayes' theorem to find the probability that a candidate comes from India given that they passed the exam.

Let $P(\text{Pass})$ be the total probability of a candidate passing the exam, which is calculated using the law of total probability: $P(\text{Pass}) = \sum [P(\text{Pass} | \text{Country}) \times P(\text{Country})]$ $P(\text{Pass}) = (0.40 \times 0.22) + (0.42 \times 0.21) + (0.39 \times 0.14) + (0.31 \times 0.44)$ $P(\text{Pass}) = 0.0880 + 0.0882 + 0.0546 + 0.1364 = 0.3672$

Now, we find the conditional probability of the candidate being from India given they passed: $P(\text{India} | \text{Pass}) = \frac{P(\text{Pass} | \text{India}) \times P(\text{India})}{P(\text{Pass})}$ $P(\text{India} | \text{Pass}) = \frac{0.0882}{0.3672} \approx 0.24019 \text{ or } 24\%$

The probability is closest to 24%.