
Explanation:
7.2`^2 = 5^2 + \text{VaR}{\text{HiEdge}}^2 \ 51.84 = 25 + \text{VaR}{\text{HiEdge}}^2 \ \text{VaR}{\text{HiEdge}}^2 = 51.84 - 25 = 26.84 \ \text{VaR}{\text{HiEdge}} = \sqrt{26.84} = 5.180 \text{ million}
\text{VaR}(T \text{ days}) = \text{VaR}(1 \text{ day}) \times \text{square root of } T
\text{VaR}(1 \text{ day}) = \frac{\text{VaR}(T \text{ days})}{(\text{square root of } T)}
\text{VaR}(1 \text{ day}) = \frac{5,180,000}{250^{0.5}} = 327,612
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Q.3151 Kinetic Financial manages portfolios of large multinational companies consisting of low-beta stock. One of their fund invested in Goodman fertilizers and HiEdge Autos. The risk analyst of Kinetic recently estimated that the annual VaR at a 95% confidence level, assuming a 250-day year for the entire portfolio, was $7.2 million based on the portfolio's market value of $65 million and a correlation coefficient between Goodman and HiEdge of zero. If the annual loss in Goodman's stock is only expected to exceed $5 million five percent of the time, then what is the daily expected loss for HiEdge's stock that will be exceeded five percent of the time?
A
$2,500,670
B
$327,612
C
$5,180,000
D
$107,360