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Explanation:
The correct answer is C.
\frac{W \times (0.0721 + 2.326 \times 0.0675) + 413 \times (0.00524 + 2.326 \times 0.00463)}{2} = \`$95.06`2m0.5W(0.229105) + 3.3059 = \$95.06`2m
W = \frac{`$91.75`606}{0.1145525}
= `$801`
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Q.3943 A liquidity division for HTC bank invests in shares and a commodity. The mid-market value of the position in shares is while the mid-market value of the position in the commodity is $413. The mean and standard deviation of the bid-offer spread for the shares are $1.24 and $1.02, respectively. On the other hand, the mean and standard deviation of the bid-offer spread for the commodity are $0.67 and $0.34. Further, the mean and standard deviation of the proportional bid-offer spread for the shares is 0.0721 and 0.0675, respectively, while the mean and standard deviation of the proportional bid-offer spread for the commodity is 0.00524 and 0.00463, respectively. Assuming that the distribution of the spreads is normal, and the cost of liquidation at the 99% confidence level in a stressed market condition is $95.062, calculate W, the mid-market value of the position in shares.
A
$905
B
$809
C
$801
D
$1,579