First recall that for the standardized Gumbel, $\mu = 0$, $\sigma = 1$

$$x = \mu - \sigma \ln\left[-\ln(p)\right]$$

The 5% quantile is: $0 - (1) \ln\left[-\ln(0.05)\right] = -1.0972$The 95$0- (1) \ln\left[-\ln(0.95)\right] = 2.9702$ The 99% quantile is:$0` - (1) \ln\left[-\ln(0.99)\right] = 4.6001$