First recall that for the standardized Gumbel, μ=0, σ=1
x=μ−σln[−ln(p)]
The 5% quantile is: $0 - (1) \ln\left[-\ln(0.05)\right] = -1.0972The950- (1) \ln\left[-\ln(0.95)\right] = 2.9702$ The 99% quantile is:0‘−(1)ln[−ln(0.99)]=4.6001
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Q.4000 For the standardized Gumbel, determine the 5% quantile, 95% quantile and the 99% quantile, respectively.
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Last updated: July 5, 2026 at 07:18
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A
-1.0972; 2.9702; 4.6001
B
-2.0845; 0.0052; 0.0041
C
4.5614; 3.8542; 2.7823
D
-1.0965; 0.0052; -2.0485
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Q.4000 For the standardized Gumbel, determine the 5% quantile, 95% quantile and the 99% quantile, respectively. | Financial Risk Manager Part 2 Quiz - LeetQuiz
